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How to render an XML Block into XHTML (PHP script)

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Hakim Bouras

Wednesday 27 May 2009 11:58:38 pm

Hi,

I am building a light newsletter feature. The body of the newsletter is contained in an XML Block attribute of an eZ object.

In my PHP client script, how can I render this XML Block into XHTML (used in the emails body) ?

<i>(I need somehow the equivalent of the template operator attribute_view_gui attribute=xml_block_body)</i>

Also would you have an idea how to convert the XHTML to plain text ?

Thanks
Hakim

Damien Pobel

Wednesday 03 June 2009 3:20:52 am

Hi Hakim,

To get the XHTML output of an XML Block attribute, you can write something like :

$dataMap = $node->attribute( 'data_map' );
$output = $dataMap['your_attribute_identifier']->attribute( 'content' )->attribute( 'output' );
$xhtml = $ouput->attribute( 'output_text' );

And to convert the XHTML to plain text, you can use the strip_tags PHP function [1]

[1] http://php.net/strip_tags

Damien
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Hakim Bouras

Thursday 04 June 2009 4:38:24 am

Hi Damien,

Thanks a lot for your help.

Actually I had to change a small thing to make it work : to use the method "outputText()" instead of the attribute "output" (but this is maybe due to the fact I am using a version 4.1).

$output = $dataMap['your_attribute_identifier']->attribute( 'content')->attribute( 'output' );
$xhtml = $output->outputText();

Cheers,
Hakim

André R.

Thursday 04 June 2009 6:02:24 am

Hakim: what class is $output? ( call "var_dump($output);" for instance)

$ouput->attribute( 'output_text' ); should have worked, as it uses outputText() in eZXMLOutputHandler, but if you have another output handler for some reason, then it might not work.

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Hakim Bouras

Friday 05 June 2009 4:50:45 am

I retried the code provided by Damien, and in fact it is working fine. I probably missed something the first time I tried.

Thanks again for your help, and sorry for the burden,
Hakim