a variable witch is defind as integer becomes an array

Tuesday 18 September 2007 5:57:44 am

Hello
In the code down i can't understand how it is possible variable $last=0 witch has a value 0
to become an array with value few rows down {set lastlevel=$last.level} . In {set lastlevel=$last.level} variable last is already array and has value. How it happens?

Please help

$last=0
{*?template charset="utf-8"?*}

{def $depth=1 $last=0 $lastlevel=0 $x=1}
{def $mainMenu=treemenu( $module_result.path, $module_result.node_id,
, 0, 4)}
<ol>
{foreach $mainMenu as $menu}

{set lastlevel=$last.level}
{if and($lastlevel|ne(0), $lastlevel|gt($menu.level))}
</ol>
</li>
{set lastlevel=$lastlevel|sub(1)}
{/if}
<li>
{if and($last | ne(0), $last.level|lt($menu.level))}
<ol>
<li{$menu.is_selected|choose('',' class="selected"')}>
{/if}
<a {$menu.is_selected|choose('','class="selected"')}
href={$menu.url_alias|ezurl}>{$menu.text|shorten(25)}</a>
</li>

{set last=$menu}
{/foreach}

{while $depth |gt(1)}
</li>
</ol>
{set depth=$depth|sub(1)}
{/while}
</ol>

Tuesday 18 September 2007 6:55:42 am

int the comment in this page http://ez.no/doc/ez_publish/technical_manual/3_8/reference/template_operators/miscellaneous/treemenu

Tuesday 18 September 2007 11:54:46 pm

Hmmm ...
I think that in first interation $lastlevel is empty and $last is zero so i don't understand how can be done $lastlevel|ne(0) when there is no value for $lastlevel.
i think it is some bug ...